OpenWeathermap: Get forecast temperature current day 15:00

Configuration
#1

Hello together,

I am usingf the openweathermap integration to get some forecast data.
I figured out that there is some forecast data available all 3 hours:

Screenshot 2023-05-26 at 08.14.34
Screenshot 2023-05-26 at 08.14.341886×1228 237 KB

I would have for the current day always the value at 15:00.
I did not get it managed and need your support.

I get it managed to get all the values, but not the dedicated I want:

"{{ state_attr('weather.openweathermap', 'forecast') }}"

I need to know how to get exactly that one value from example
datetime: '2023-05-26T15:00:00+00:00'

Thank you.

#2

Not sure if it is always the same list, but in the knmi weather i use it is, so i always use attribute [1]:

min:    {{state_attr("weather.knmi","forecast")[1].templow|round}}.

if so, in your forecast to get 15:00 you could use something like this

"{{ state_attr('weather.openweathermap', 'forecast')[2] }}"
1 Like
#3 
{% set day = (today_at('00:00') + timedelta(days=0)).strftime('%F') %}
{{ state_attr('weather.openweathermap','forecast') | selectattr('datetime', 'match', '^'~day) | selectattr('datetime', 'match', '^.*(15:00)') | map(attribute='temperature') | list }}

this is a bit more than needed but note that ‘day’ you can change by altering the timedelta …e.g. if you want to know for tomorrow

1 Like
#4

Thank you both!

I tested both variants in my template:

"{{ state_attr('weather.openweathermap', 'forecast')[2].datetime }}"
"{{ state_attr('weather.openweathermap', 'forecast')[2].temperature }}"

{% set day = (today_at('00:00') + timedelta(days=0)).strftime('%F') %}
{{ state_attr('weather.openweathermap','forecast') | selectattr('datetime', 'match', '^'~day) | selectattr('datetime', 'match', '^.*(15:00)') | map(attribute='temperature') | list }}

Current output:

"2023-05-26T15:00:00+00:00"
"21.8"

[21.8]

Will see if the first option always dfelivers the 15:00 value.

And for further usage I will check if I have to remove the brakets for the second try.

Thanks.

#5

To complete:
Solution 1 always delivers the second value in the array, so it might switch from 15:00 to 18:00 based on the time of the day.

Solution 2 seems to be the best! I only have to replace the brackets.