Template sensor to count how many friday in a month

Configuration
1

Hi,
is there a possibility to count how many friday are there in every current month?
The results should be a specif number (4 or 5) to make an automation.
Any ideas?

Thanks in advance.
Regards,

Alessandro

2

The following should report the number of Fridays in the current month.

{% set nth = 5 %}
{% set month = now().month %}
{% set isoweekday = 5 %}
{% set d = now().date().replace(month=month).replace(day=1) %}
{% set adj = (isoweekday - d.isoweekday()) % 7 %}
{% set fifth = d + timedelta(days=adj) + timedelta(weeks=nth-1) %}
{{ 4 if fifth.month > month else 5 }}

Or the condensed version…

{% set d = now().date().replace(day=1) %}
{% set fifth = d + timedelta(days=((5 - d.isoweekday()) % 7)) + timedelta(weeks=4) %}
{{ 4 if fifth.month > now().month else 5 }}

These are slightly modified versions of Taras’ post found here

EDIT: Addressed redundant replace function brought up by tom_l

3

I don’t get this bit:

You seem to be replacing the month in this month’s date with this month. Which strikes me as redundant. I’m obviously misunderstanding something.

4

You’re absolutely right. That was just lazy editing on my part… I was playing around with a “next month” version and just did a find/replace:

{% set next_month = now().month + 1 %}
{%- set d = now().date().replace(month=next_month).replace(day=1) %}
{%- set fifth = d + timedelta(days=((5 - d.isoweekday()) % 7)) + timedelta(weeks=4) %}
{{- 4 if fifth.month > next_month else 5 }}
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