ESP Home Binary Sensor IF

ESPHome
1

Hi Guys

I’m new to ESPHome and its a stupid question. but how do i get this to run?

It should the sensor 1 on if all the others are off.

image

Thank you for your help!

2

Hi and welcome to the forum.

Could you please paste the actual configuration text rather than an image of the text. This helps us help you as we can copy/edit/paste easily. Instructions on formatting your pasted text are outlined in point 11 here.

3

my bad.

binary_sensor:
  - platform: gpio
    pin: GPIO13
    name: "Lüftungsschalter Wohnzimmer 0"
    

  - platform: template
    name: "Lüftungsschalter Wohnzimmer 1"
    lambda: |-
      if (id("Lüftungsschalter Wohnzimmer 0").state) {
        return true;
      } else {
        return false;
      }

  - platform: gpio
    pin: GPIO14
    name: "Lüftungsschalter Wohnzimmer 2"
    
  
  - platform: gpio
    pin: GPIO26
    name: "Lüftungsschalter Wohnzimmer 3"
4

Did you mean sensor 1?

Sensor 1 has the template, sensor 2 is a GPIO binary sensor.

binary_sensor:
  - platform: gpio
    pin: GPIO13
    name: "Lüftungsschalter Wohnzimmer 0"
    id: "LW0"
    
  - platform: template
    name: "Lüftungsschalter Wohnzimmer 1"
    lambda: |-
      if (id("LW0").state) && (id("LW2").state) && (id("LW3").state) {
        return true;
      } else {
        return false;
      }

  - platform: gpio
    pin: GPIO14
    name: "Lüftungsschalter Wohnzimmer 2"
    id: "LW2"
  
  - platform: gpio
    pin: GPIO26
    name: "Lüftungsschalter Wohnzimmer 3"
    id: "LW3"
5

Sorry yes sensor 1.

if not sensor 0 & sensor 2 & sensor 3
then sensor 1 true
else
sensor 1 false

6 
  - platform: template
    name: "Lüftungsschalter Wohnzimmer 1"
    lambda: |-
      if !(id("LW0").state) && (id("LW2").state) && (id("LW3").state) {
        return true;
      } else {
        return false;
      }
7

Thanks for helping.

But I’m getting this error while compiling.

image
image652×505 13.6 KB

What is the problem?

8

Remove the quotes from around the ids.


  - platform: template
    name: "Lüftungsschalter Wohnzimmer 1"
    lambda: |-
      if !(id(LW0).state) && (id(LW2).state) && (id(LW3).state) {
        return true;
      } else {
        return false;
      }
1 Like
9

Thanks alot

1 Like