Switch Icon Changed/Switch to Sensor

Configuration
1

Hi guys,

is there a way to have the old switch icon back? Like in the Demo?
This is what I have now:

I would like the old one back:

Any ideea how can I can revert?

Regards

1 Like
2

Add this in your configuration.yaml under homeassistant:

  customize: 
    switch.ENTITY_ID:
      assumed_state: false
2 Likes
3

Thank you. Now they are back. :smiley:

Another question on this idea, is there a way to hide that switch at all?
I have some door sensors that appear as switches it would be great to hide that switch icon for them. Since that is triggered only by opening the door.

4 
  customize:    
      switch.ENTITY_ID:
         hidden: true
1 Like
5

This will hide the entire element. I just want to hide the blue switch in the left. And keep the element as a “view only”.

I don’t want for somebody to alter it by mistake from the GUI. It will change his status only by automation.

6

Ahh, I understand. I am not sure if that is possible.

Ideally your switch should have been added as a binary sensor, but that will probably require updating some code.

7

Yes, I know. But I am not able to add it as a sensor. Thank you for your support.

Maybe as a feature request, it would be great to have the option to make a switch(or some other item) “view only”. In order to prevent unwanted actions.

8

You can hide that switch and use a binary_sensor to show if it’s ON or OFF

1 Like
9

I would put a “Say what???” meme here :laughing: This is new for me. Thanks.

I would have to read more on it, because it is not simple as it looks.
I assume that states.switch.ENTITY_ID.state is the one I should check.

10

Yes, use something like this:

binary_sensor:
  platform: template
  sensors:
    viewonlysensor:
      value_template: "{%if states.switch.ENTITY_ID.state == 'on' %}ON{%elif states.switch.ENTITY_ID.state == 'off' %}OFF{% endif %}"
      friendly_name: 'Switch is on?'

The if, elif and endif are for some kind of customization of what the sensor shows, if you just wanna show “plane state”, just use:

binary_sensor:
  platform: template
  sensors:
    viewonlysensor:
      value_template: "{{ states.switch.ENTITY_ID.state }}"
      friendly_name: 'Switch is on?'
1 Like
11

Thank you.
Yes, I was intrested in just a plane status. I used the same configuration like in your second example, but I had to add after the state: == “on”. I think the sensor is just true or false, no?

states.switch.Entity_ID.state == “on”
And it will return true or false.